This last chapter was a very important chapter because it teaches us methods of solving all sorts of real-world problems that involve more than one variable.
Write a wind, water current, or puzzle word problem that you think is challenging. Then solve the problem, providing only the answer in the same post. The most challenging two problems from the class with the correct answers will receive bonus.
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There are two girls named Rashandala and Shanaynay. Rashandala is 8/7 as old as Shanaynay is. Next year, Rashandala's age will be one third as old as Shanaynay this year and 9/11 as old as Shanaynay next year. How old are the girls?
ReplyDeleteA: Rashandala = 24 yrs old
Shanaynay = 21 yrs old :D
The sum of the digits of a two digit number is eight and their difference is six. If the value of the number is less than fifty, what is the number?
ReplyDeleteu=7
t=1
= 17
A boat can go 100 km downstream in 2 hours, the same time it takes for it to go 80 km upstream. Find the speed of the boat in still water and the speed of the current.
ReplyDeleteSpeed of Boat in Still Water: 45 km/hr
Speed of Current: 5 km/hr
This is Jane by the way! hyunjitop = Jane Yeo. :D
ReplyDeleteOkay this is my PUZZLE problem:
Jane's age equals the sum of TOP's age and Gdragon's age. Two years ago, Jane was 4 times as old as Gdragon was, and two years from now, Jane will be 1.4 times as old as TOP will be. How old is each NOW? :D I think you have to use three variables.
Jane being expressed as J
TOP being expressed as T
and Gdragon being expressed as G.
Jane is 26 years old.
TOP is 18 years old.
Gdragon is 8 years old.
There is a fraction with a fraction as a numerator, and a whole number denominator. The numerator's numerator is a two digit number and the denominator is also a two digit number. If you flip the fraction's numerator's numerator, it equals the denominator of the fraction's numerator. The flipped numerator is 18 and its sum of its 2 digits are 12. The denominator of the main fraction is 75 times the numerator. What is the fraction?
ReplyDeleteIt takes 1 hour for an airplane to fly from Seoul to Busan. However, it takes 1 hour and 30 minutes to fly from Busan to Seoul. Wind blows from Seoul to Busan. The distance from Seoul to Busan is 410 Km. How fast is an airplane in still air and what is wind speed.
ReplyDeleteairplane speed in still air = 345 km/h
wind speed = 65 km/h
-Sukwon
Habin in is 8/5 times older than Habin Junior. They're age combined is 104 years. What will they're age be in 4 years time?
ReplyDeleteAnswer Habin- 64, in 4 yeras, 68
Habin Junior- 40 in 4 years 44
This last chapter was a very important chapter because it teaches us methods of solving all sorts of real-world problems that involve more than one variable.
ReplyDeleteWrite a wind, water current, or puzzle word problem that you think is challenging. Then solve the problem, providing only the answer in the same post. The most challenging two problems from the class with the correct answers will receive bonus.
Four years ago, Marie was 3/4's of her brother's age. She is now 10 years younger than her brother. Her brother is 8 years older than his cousin. Marie and her cousin's age combined is 102. How old are each?
Brother: 52 Cousin: 60 Marie:50
Brian Byun 8B
ReplyDeleteThe mechanical bird flies at 40 mph in still air. The bird tends to speed up when the wind against it is stronger. The distance the bird travels 126 miles going and coming back, 2 hours are taken when flying with the wind. What is the rate of the wind?
Wind Speed= 6 mph
Joseph and his cousins Marie and Sarah are either older or younger than each other. Ten years ago, Joseph's age was 1/5 of Sarah's age. Sarah is 8 years older than Marie. Their combined age is 57. How old are they?
ReplyDeleteJoseph 15,
Marie 17,
Sarah 25
Jerica is 5 years older than her sister. Last year, Jerica was twice as old as her sister was. How old are they now?
ReplyDeleteJ=S+5
J-1= 2(S-1)
J-1=2S-2
J=2S-1
2S-1=s+5
S=6.
Her sister is 6 years old, and Jerica is 11.
This last chapter was a very important chapter because it teaches us methods of solving all sorts of real-world problems that involve more than one variable.
ReplyDeleteWrite a wind, water current, or puzzle word problem that you think is challenging. Then solve the problem, providing only the answer in the same post. The most challenging two problems from the class with the correct answers will receive bonus.
Elaine's age equals the sum of her grandpa and grandma's age. Two years ago, Elaine was 4 times as old as grandma was, and two years from now, Elaine will be 1.4 times as old as Grandpa will be. How old is each now?
Elaine : 26
grandpa: 18
Grandma: 8